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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
Amitesh buys a pen, a pencil and an eraser for 41. If the least cost of any of the three items is 12 and it is known that a pen costs less than a pencil and an eraser costs more than a pencil, answer the following questions:
What is the cost of the pen?
CorrectAnswer :a
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
In both cases, the cost of the pen is 12.
IncorrectAnswer :a
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
In both cases, the cost of the pen is 12.

Question 2 of 5
Amitesh buys a pen, a pencil and an eraser for 41. If the least cost of any of the three items is 12 and it is known that a pen costs less than a pencil and an eraser costs more than a pencil, answer the following questions:
If it is known that the eraser’s cost is not divisible by 4, the cost of the pencil could be:
CorrectAnswer : c
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
If the cost of the eraser is not divisible by 4, it means that Case 2 holds true. For this case, the cost of the pencil is 14.
IncorrectAnswer : c
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
If the cost of the eraser is not divisible by 4, it means that Case 2 holds true. For this case, the cost of the pencil is 14.

Question 3 of 5
A naughty boy Amrit watches an innings of Sachin Tendulkar and acts according to the number of runs he sees Sachin scoring. The details of these are given below.
1 run Place an orange in the basket
2 runs Place a mango in the basket
3 runs Place a pear in the basket
4 runs Remove a pear and a mango from the basket
One fine day, at the start of the match, the basket is empty. The sequence of runs scored by Sachin in that innings are given as 11232411234232341121314.
At the end of the above innings, how many more oranges were there compared to mangoes inside the basket? (The Basket was empty initially).
CorrectAnswer : c
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
Amrit would place eight oranges in the basket (as there are eight 1’s). For the mangoes, he would place six mangoes (number of 2’s) and remove four mangoes (number of 4’s) from the basket. Thus, there would be 2 mangoes and 8 oranges in the basket.
A total of 8 2 = 6 extra oranges in the basket.
Option (c) is correct.
IncorrectAnswer : c
The given condition says that Pen<Pencil<Eraser Also, since the least cost of the three is Rs. 12, if we allocate a minimum of 12 to each we use up 36 out of the 41 available. The remaining 5 can be distributed as 0,1,4 or 0,2 and 3 giving possible values of Case 1: 12,13 and 16 or Case 2: 12,14 and 15.
Amrit would place eight oranges in the basket (as there are eight 1’s). For the mangoes, he would place six mangoes (number of 2’s) and remove four mangoes (number of 4’s) from the basket. Thus, there would be 2 mangoes and 8 oranges in the basket.
A total of 8 2 = 6 extra oranges in the basket.
Option (c) is correct.

Question 4 of 5
In the famous Bel Air Apartments in Ranchi, there are three watchmen meant to protect the precious fruits in the campus. However, one day a thief got in without being noticed and stole some precious mangoes. On the way out however, he was confronted by the three watchmen, the first two of whom asked him to part with 1/3 of the fruits and one more. T he last asked him to part with 1/5th of the mangoes and 4 more. As a result he had no mangoes left. What
was the number of mangoes he had stolen?
CorrectAnswer : C
Solve using trial and error Option (c) fits the situation as if we start with 15 mangoes, the following structure would take place:
Start with 15 mangoes ® First watchman takes 1/3^{rd}
+1 more= 5 + 1 = 6 mangoes ® 9 mangoes left.
Second watchman takes ® 1/3^{rd} + 1 more = 3+1 = 4 mangoes 5 mangoes left.
Third watchman takes ® 1/5^{th} + 4 more = 1 + 45
mangoes ® 0 mangoes left.
IncorrectAnswer : C
Solve using trial and error Option (c) fits the situation as if we start with 15 mangoes, the following structure would take place:
Start with 15 mangoes ® First watchman takes 1/3^{rd}
+1 more= 5 + 1 = 6 mangoes ® 9 mangoes left.
Second watchman takes ® 1/3^{rd} + 1 more = 3+1 = 4 mangoes 5 mangoes left.
Third watchman takes ® 1/5^{th} + 4 more = 1 + 45
mangoes ® 0 mangoes left.

Question 5 of 5
A hundred and twenty digit number is formed by writing the first x natural numbers in front of each other as 12345678910111213.. Find the remainder when this number is divided by 8.
CorrectAnswer :a
The last 3 digits of the number would determine the remainder when it is divided by 8. The number upto the 120th digit would be 1234567891011… 646. 646 divided by 8 gives us a remainder of 6.
IncorrectAnswer :a
The last 3 digits of the number would determine the remainder when it is divided by 8. The number upto the 120th digit would be 1234567891011… 646. 646 divided by 8 gives us a remainder of 6.
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